{
  "schema_version": 1,
  "kind": "ConceptView",
  "producer": "concept-view-1",
  "concept_id": "urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948",
  "labels": {
    "zh-CN": "舒尔引理",
    "en": "Schur’s lemma"
  },
  "alternative_labels": [],
  "scope_note": "",
  "identity_status": "active",
  "identity_revision": "30e39c99400fb4032d4b0b343fcdb859eaa0047bc4ef10df75ae93b6d131dec5",
  "occurrences": [
    {
      "concept_id": "urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948",
      "book_id": "szekeres",
      "edition_id": "source-snapshot-bc3404156f6e",
      "lang": "zh-CN",
      "route": "zh/chapter-04/04-introduction-to-group-representation-theory",
      "anchor": "first-6d7eb6cc7322de42f7e0-zh",
      "chapter": "4",
      "section": "4.4",
      "offset": 11874,
      "range": [
        16972,
        18065
      ],
      "source_revision": "8659a22bf0394df6e0f0547cc91ed5a8dd18c3b22a3aa2463bbac9fbfc4f313c",
      "source_category": "translation",
      "review_status": "unreviewed",
      "role": "theorem",
      "role_basis": {
        "kind": "registered-source-environment",
        "registered_position": {
          "route": "zh/chapter-04/04-introduction-to-group-representation-theory",
          "lang": "zh-CN",
          "section": "4.4",
          "signal": "named-theorem",
          "label": "舒尔引理",
          "english": "Schur’s lemma",
          "offset": 10556
        }
      },
      "label": "> [!theorem] <a class=\"object-permalink\" href=\"#theorem-4-6\">定理 4.6</a> · 舒尔引理 (Schur’s lemma)",
      "context": {
        "range": [
          16972,
          18065
        ],
        "quote": "\n\n> [!theorem] <a class=\"object-permalink\" href=\"#theorem-4-6\">定理 4.6</a> · 舒尔引理 (Schur’s lemma)\n>\n> （舒尔引理）设 $T _ { 1 } : G \\to G L ( V _ { 1 } )$ 与 $T _ { 2 } : G \\to G L ( V _ { 2 } )$ 是群 $G$ 的两个不可约表示，且 $A : V _ { 1 } \\to V _ { 2 }$ 是一个交织算符，使得\n>\n> $$\n> T _ {2} (g) A = A T _ {1} (g) \\text {   for   all   } g \\in G.\n> $$\n>\n> 于是 $A = 0$ 或 $A$ 是同构，此时这两个表示等价，$T _ { 1 } \\sim T _ { 2 }$\n\n> [!proof]- 证明\n>\n> 设 $v \\in$ $\\ker$ $A \\subseteq V _ { 1 }$。则\n>\n> $$\n> A T _ {1} (g) v = T _ {2} (g) A v = 0\n> $$\n>\n> 因此 $T _ { 1 } ( g ) v \\in$ $\\ker$ $A$。于是 $\\ker$ $A$ 是表示 $T _ { 1 }$ 的不变子空间。由于 $T _ { 1 }$ 是不可约表示，我们有或者 $\\ker$ $A = V _ { 1 }$，此时 $A = 0 _ { i }$，或者 $\\ker$ $A = \\{ 0 \\}$。在后一种情形中，$A$ 是一对一的。为表明它是同构，只需表明它是满射。这由以下事实推出：$\\operatorname{im}$ $A \\subset V _ { 2 }$ 是表示 $T _ { 2 }$ 的不变子空间\n>\n> $$\n> T _ {2} (g) (\\mathrm{im} A) = T _ {2} (g) A \\left(V _ {1}\\right) = A T _ {1} (g) \\left(V _ {1}\\right) \\subseteq A \\left(V _ {1}\\right) = \\mathrm{im} A.\n> $$\n>\n> 由于 $T _ { 2 }$ 是不可约表示，我们有 $\\operatorname{im}$ $A = \\{ 0 \\}$ 或 $\\operatorname{im}$ $A = V _ { 2 }$ 。在第一种情形中 $A = 0$ ，而在第二种情形中 $A$ 是满射。舒尔引理得证。\n",
        "quote_sha256": "10f2461c9294b193cd106fa0ef9f80676cf552601bd7b063b34aa18634c4e576",
        "environment": "theorem",
        "excerpt_omitted": false
      },
      "parallel_readings": [
        {
          "route": "en/chapter-04/04-introduction-to-group-representation-theory",
          "lang": "en",
          "source_category": "original_transcription",
          "basis": "registered-book-edition-section-language-context; not-concept-equivalence"
        }
      ],
      "id": "occ-1bb6de943d307a0620fcdadd"
    },
    {
      "concept_id": "urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948",
      "book_id": "szekeres",
      "edition_id": "source-snapshot-bc3404156f6e",
      "lang": "en",
      "route": "en/chapter-04/04-introduction-to-group-representation-theory",
      "anchor": "first-6d7eb6cc7322de42f7e0-en",
      "chapter": "4",
      "section": "4.4",
      "offset": 13803,
      "range": [
        18393,
        19962
      ],
      "source_revision": "9ba0357bc9fe2cf27435fc71decca231bb93b8a3a84cf95591397d0b6b814384",
      "source_category": "original_transcription",
      "review_status": "unreviewed",
      "role": "theorem",
      "role_basis": {
        "kind": "registered-source-environment",
        "registered_position": {
          "route": "en/chapter-04/04-introduction-to-group-representation-theory",
          "lang": "en",
          "section": "4.4",
          "signal": "named-theorem",
          "label": "Schur’s lemma",
          "english": "Schur’s lemma",
          "offset": 13733
        }
      },
      "label": "> [!theorem] <a class=\"object-permalink\" href=\"#theorem-4-6\">Theorem 4.6</a> · Schur’s lemma",
      "context": {
        "range": [
          18393,
          19962
        ],
        "quote": "\n\n> [!theorem] <a class=\"object-permalink\" href=\"#theorem-4-6\">Theorem 4.6</a> · Schur’s lemma\n>\n> (Schur’s lemma) Let $T _ { 1 } : G \\to G L ( V _ { 1 } )$ and $T _ { 2 } : G \\to G L ( V _ { 2 } )$ be two irreducible representations of a group $G$, and $A : V _ { 1 } \\to V _ { 2 }$ an intertwining operator such that\n>\n> $$\n> T _ {2} (g) A = A T _ {1} (g) \\text {   for   all   } g \\in G.\n> $$\n>\n> Then either $A = 0$ or $A$ is an isomorphism, in which case the two representations are equivalent, $T _ { 1 } \\sim T _ { 2 }$\n\n> [!proof]- Proof\n>\n> Let $v \\in$ $\\ker$ $A \\subseteq V _ { 1 }$ . Then\n>\n> $$\n> A T _ {1} (g) v = T _ {2} (g) A v = 0\n> $$\n>\n> so that $T _ { 1 } ( g ) v \\in$ $\\ker$ $A$. Hence $\\ker$ $A$ is an invariant subspace of the representation $T _ { 1 }$ . As $T _ { 1 }$ is an irreducible representation we have that either $\\ker$ $A = V _ { 1 }$ , in which case $A = 0 _ { i }$ or $\\ker$ $A = \\{ 0 \\}$ . In the latter case $A$ is one-to-one. To show it is an isomorphism it is only necessary to show that it is onto. This follows from the fact that $\\operatorname{im}$ $A \\subset V _ { 2 }$ is an invarian subspace of the representation $T _ { 2 }$\n>\n> $$\n> T _ {2} (g) (\\mathrm{im} A) = T _ {2} (g) A \\left(V _ {1}\\right) = A T _ {1} (g) \\left(V _ {1}\\right) \\subseteq A \\left(V _ {1}\\right) = \\mathrm{im} A.\n> $$\n>\n> Since $T _ { 2 }$ is an irreducible representation we have either $\\operatorname{im}$ $A = \\{ 0 \\}$ or $\\operatorname{im}$ $A = V _ { 2 }$ . In the first case $A = 0$ , while in the second $A$ is onto. Schur’s lemma is proved.\n",
        "quote_sha256": "b973a8e5797b3c59b8aa3aa22fca113d76a052fac5ce577ba6d7de1ae2176d67",
        "environment": "theorem",
        "excerpt_omitted": false
      },
      "parallel_readings": [
        {
          "route": "zh/chapter-04/04-introduction-to-group-representation-theory",
          "lang": "zh-CN",
          "source_category": "translation",
          "basis": "registered-book-edition-section-language-context; not-concept-equivalence"
        }
      ],
      "id": "occ-1d7edaa9ecb989535877130f"
    },
    {
      "concept_id": "urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948",
      "book_id": "woit-qtgr",
      "edition_id": "2025-10-20",
      "lang": "zh-CN",
      "route": "books/woit-qtgr/2025-10-20/zh/chapter-02/01-some-representation-theory",
      "anchor": "first-e575a0c33aad56892410-zh",
      "chapter": "2",
      "section": "2.1",
      "offset": 6790,
      "range": [
        16973,
        17279
      ],
      "source_revision": "42b32dda09af12d2236451f0c9b29db8c863f217a1374b2e7d4d7efd1d69b961",
      "source_category": "translation",
      "review_status": "unreviewed",
      "role": "occurrence",
      "role_basis": {
        "kind": "explicit-source-uuid-marker"
      },
      "label": "舒尔引理(Schur’s lemma)",
      "context": {
        "range": [
          16886,
          17526
        ],
        "quote": "\n> [!theorem] 定理 · <a href=\"../../../../../concepts/representation-theory/schur-lemma\"><u class=\"concept-term\" data-concept-reference=\"concepts/representation-theory/schur-lemma\" data-concept-identity=\"urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948\" data-concept-route=\"/concept-identities#concept-023d3b84-da9a-4667-8674-d5b9ccbed948\" id=\"first-e575a0c33aad56892410-zh\">舒尔引理(Schur’s lemma)</u></a>\n> <span id=\"source-block-2034\" class=\"block-anchor\"></span>\n>\n> <span class=\"author-definition-label\" aria-hidden=\"true\">定理（舒尔引理）。</span>若复表示 $(\\pi,V)$ 不可约，则与所有 $\\pi(g)$ 交换的线性映射 $M:V\\to V$ 只有 $\\lambda\\mathbf{1}$，即乘以标量 $\\lambda\\in\\mathbf{C}$。\n",
        "quote_sha256": "53c480c5b881240222809586d894687ab85b8c0de5863113e3c391af502b9b81",
        "environment": "theorem",
        "excerpt_omitted": false
      },
      "parallel_readings": [
        {
          "route": "books/woit-qtgr/2025-10-20/en/chapter-02/01-some-representation-theory",
          "lang": "en",
          "source_category": "original_transcription",
          "basis": "registered-book-edition-section-language-context; not-concept-equivalence"
        }
      ],
      "id": "occ-574da2fdbe17b833dab24ab8"
    },
    {
      "concept_id": "urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948",
      "book_id": "woit-qtgr",
      "edition_id": "2025-10-20",
      "lang": "en",
      "route": "books/woit-qtgr/2025-10-20/en/chapter-02/01-some-representation-theory",
      "anchor": "first-e575a0c33aad56892410-en",
      "chapter": "2",
      "section": "2.1",
      "offset": 7356,
      "range": [
        15760,
        16060
      ],
      "source_revision": "fd6acd71ca250c6760bd4f303aeeb212d709a4c9cb7af7a9476be4a1a7ea289c",
      "source_category": "original_transcription",
      "review_status": "ai-transcription-compared",
      "role": "occurrence",
      "role_basis": {
        "kind": "explicit-source-uuid-marker"
      },
      "label": "Schur’s lemma",
      "context": {
        "range": [
          15668,
          16417
        ],
        "quote": "\n> [!theorem] Theorem · <a href=\"../../../../../concepts/representation-theory/schur-lemma\"><u class=\"concept-term\" data-concept-reference=\"concepts/representation-theory/schur-lemma\" data-concept-identity=\"urn:uuid:023d3b84-da9a-4667-8674-d5b9ccbed948\" data-concept-route=\"/concept-identities#concept-023d3b84-da9a-4667-8674-d5b9ccbed948\" id=\"first-e575a0c33aad56892410-en\">Schur’s lemma</u></a>\n> <span id=\"source-block-2034\" class=\"block-anchor\"></span>\n>\n> <span class=\"author-definition-label\" aria-hidden=\"true\">Theorem (Schur’s lemma).</span> If a complex representation $(\\pi,V)$ is irreducible, then the only linear maps $M:V\\to V$ commuting with all the $\\pi(g)$ are $\\lambda\\mathbf{1}$, multiplication by a scalar $\\lambda\\in\\mathbf{C}$.\n",
        "quote_sha256": "0dbb0c28c1340b33db63256954165dde7a85116a428c1b433716b4dac02916a6",
        "environment": "theorem",
        "excerpt_omitted": false
      },
      "parallel_readings": [
        {
          "route": "books/woit-qtgr/2025-10-20/zh/chapter-02/01-some-representation-theory",
          "lang": "zh-CN",
          "source_category": "translation",
          "basis": "registered-book-edition-section-language-context; not-concept-equivalence"
        }
      ],
      "id": "occ-fb9fc72f29caf1d1ffb639a5"
    }
  ],
  "registered_positions": [
    {
      "route": "en/chapter-04/04-introduction-to-group-representation-theory",
      "lang": "en",
      "section": "4.4",
      "signal": "named-theorem",
      "label": "Schur’s lemma",
      "english": "Schur’s lemma",
      "offset": 13733
    },
    {
      "route": "zh/chapter-04/04-introduction-to-group-representation-theory",
      "lang": "zh-CN",
      "section": "4.4",
      "signal": "named-theorem",
      "label": "舒尔引理",
      "english": "Schur’s lemma",
      "offset": 10556
    },
    {
      "route": "books/woit-qtgr/2025-10-20/en/chapter-02/01-some-representation-theory",
      "lang": "en",
      "section": "2.1",
      "signal": "term-mark",
      "label": "Schur’s lemma",
      "english": "Schur’s lemma",
      "offset": 6902
    },
    {
      "route": "books/woit-qtgr/2025-10-20/zh/chapter-02/01-some-representation-theory",
      "lang": "zh-CN",
      "section": "2.1",
      "signal": "term-mark",
      "label": "舒尔引理",
      "english": "Schur’s lemma",
      "offset": 5413
    }
  ],
  "statements": [],
  "resolved_references": [
    {
      "raw": "href=\"#theorem-4-6\"",
      "href": "#theorem-4-6",
      "range": [
        17015,
        17034
      ],
      "relation": "references",
      "target_route": "zh/chapter-04/04-introduction-to-group-representation-theory",
      "target_anchor": "theorem-4-6",
      "resolved": true,
      "reason": null,
      "source_revision": "8659a22bf0394df6e0f0547cc91ed5a8dd18c3b22a3aa2463bbac9fbfc4f313c",
      "source_route": "zh/chapter-04/04-introduction-to-group-representation-theory",
      "occurrence_id": "occ-1bb6de943d307a0620fcdadd"
    },
    {
      "raw": "href=\"#theorem-4-6\"",
      "href": "#theorem-4-6",
      "range": [
        18436,
        18455
      ],
      "relation": "references",
      "target_route": "en/chapter-04/04-introduction-to-group-representation-theory",
      "target_anchor": "theorem-4-6",
      "resolved": true,
      "reason": null,
      "source_revision": "9ba0357bc9fe2cf27435fc71decca231bb93b8a3a84cf95591397d0b6b814384",
      "source_route": "en/chapter-04/04-introduction-to-group-representation-theory",
      "occurrence_id": "occ-1d7edaa9ecb989535877130f"
    }
  ],
  "reading_order": [
    "occ-1bb6de943d307a0620fcdadd",
    "occ-1d7edaa9ecb989535877130f",
    "occ-574da2fdbe17b833dab24ab8",
    "occ-fb9fc72f29caf1d1ffb639a5"
  ],
  "recorded_dependencies": [],
  "reading_paths": [],
  "coverage": {
    "registered_positions": 4,
    "located_occurrences": 4,
    "whole_book_search_complete": false,
    "registered_positions_truncated": false,
    "independent_human_review_implied": false
  },
  "unresolved": [],
  "base_revision": "72d9ef7a463513e46f531f8b70b2416b01cc96086bf6f0dc052b82a8c85eef32",
  "optional_enrichments": []
}
