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        "quote": "\n\n> [!theorem] <a class=\"object-permalink\" href=\"#theorem-2-2\">定理 2.2</a> · 凯莱定理 (Cayley’s theorem)\n>\n> 任意$n$阶有限群都同构于排列群\n\n> [!proof]- 证明\n>\n> 对于每一个$g\\in G$，定义映射$L_{g} : G\\to G$为左乘以$g$，\n>\n> $$\n> L_{g}(x)=gx\\quad\\mathrm{where}\\quad x\\in G.\n> $$\n>\n> 由于\n>\n> $$\n> gx=gx^{\\prime}\\Longrightarrow x=x^{\\prime}\\quad\\mathrm{and}\\quad x=L_{g}(g^{-1}x)\\quad\\mathrm{for~all~}x\\in G.\n> $$\n>\n> 因此，这个映射是一一对应和可逆的。$L_g$ 因此排列 $G=\\{g_1=e,g_2,\\ldots,g_n\\}$ 的元素，并且可以被认为是$S_n$中的一个成员。它有属性 $L_g\\circ L_h=L_{gh}$，因为\n>\n> $$\n> L_{g}\\circ L_{h}(x)=g(hx)=(gh)x=L_{gh}(x),\\quad\\forall x\\in G.\n> $$\n>\n> 因此，由 $\\varphi(g)=L_g$ 定义的映射 $\\varphi:G\\to S_n$ 是一个同态，\n>\n> $$\n> \\varphi(g)\\varphi(h)=L_{g}\\circ L_{h}=L_{gh}=\\varphi(gh).\n> $$\n>\n> 此外，$\\varphi$ 是一一对应的，因为如果 $\\varphi(g)=\\varphi(h)$ 那么 $g=L_g(e)=L_h(e)=h$ 。因此，$G$ 与 $\\varphi(G)\\subseteq S_{n}$ 的子群是同构的。\n",
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