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        "quote": "爱因斯坦场方程可由变分原理导出，只需将拉格朗日量取为里奇标量，$L = R$。这被称为<u class=\"concept-term\" data-concept-identity=\"urn:uuid:5cac9313-3d4f-4510-8bac-b257c148accb\" data-concept-route=\"/concept-identities#concept-5cac9313-3d4f-4510-8bac-b257c148accb\" id=\"first-585ec3f84b40b0c0f6c5-zh\">希尔伯特拉格朗日量(Hilbert Lagrangian)</u>。对于独立变量，既可以取度量张量分量$g _ { \\mu \\nu }$，也可以取其逆张量的分量$g ^ { \\mu \\nu }$。我们将采用后者，因为它稍微更为方便（读者可以尝试针对变量$\\Phi _ { A } = g _ { \\mu \\nu }$ 调整随后的分析。我们不能直接使用欧拉–拉格朗日方程 <a href=\"#equation-18-113\" class=\"cross-reference\" id=\"xref-10-variation-principles-in-space-time-3\" data-reference=\"equation-18-113\">式 (18.113)</a>，因为$R$ 依赖于$g ^ { \\mu \\nu }$ 及其一阶和二阶导数。虽然欧拉–拉格朗日分析可以推广到包含依赖于场二阶导数的拉格朗日量（见问题18.32），但这将是一项极其复杂的计算。直接进行，我们有",
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        "quote": "Einstein’s field equations may be derived from a variation principle, by setting the Lagrangian to be the Ricci scalar, $L = R$ . This is known as the <u class=\"concept-term\" data-concept-identity=\"urn:uuid:5cac9313-3d4f-4510-8bac-b257c148accb\" data-concept-route=\"/concept-identities#concept-5cac9313-3d4f-4510-8bac-b257c148accb\" id=\"first-585ec3f84b40b0c0f6c5-en\">Hilbert Lagrangian</u>. For independent variables it is possible to take either the metric tensor components $g _ { \\mu \\nu }$ or those of the inverse tensor $g ^ { \\mu \\nu }$ . We will adopt the latter, as it is slightly more convenient (the reader may try to adapt the analysis that follows for the variables $\\Phi _ { A } = g _ { \\mu \\nu }$ . We cannot use the Euler–Lagrange equations <a href=\"#equation-18-113\" class=\"cross-reference\" id=\"xref-10-variation-principles-in-space-time-4\" data-reference=\"equation-18-113\">Eq. (18.113)</a> as they stand since $R$ is dependent on $g ^ { \\mu \\nu }$ and its first and second derivatives. While the Euler–Lagrange analysis can be extended to include Lagrangians that depend on second derivatives of the fields (see <a href=\"#problem-18-32\" class=\"cross-reference\" id=\"xref-10-variation-principles-in-space-time-5\" data-reference=\"problem-18-32\">Problem 18.32</a>), this would be a prohibitively complicated calculation. Proceeding directly, we have",
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