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        "quote": "\n\n> [!theorem] <a class=\"object-permalink\" href=\"#theorem-5-6\">定理 5.6</a> · 三角不等式 (Triangle inequality)\n>\n> （三角不等式）对于内积空间中的任意一对向量 $u$ 和 $v$，\n>\n> <span id=\"equation-5-14\" class=\"block-anchor\"></span>\n>\n> $$\n> \\| u + v \\| \\leq \\| u \\| + \\| v \\|.\\tag{5.14}\n> $$\n\n> [!proof]- 证明\n>\n> $$\n> \\begin{aligned}\n> (\\| u + v \\|) ^ {2} &= \\langle u + v | u + v \\rangle \\\\[0.4em]\n>  &= \\langle u | u \\rangle + \\langle v | v \\rangle + \\langle v | u \\rangle + \\langle u | v \\rangle \\\\[0.4em]\n>  &= \\| u \\| ^ {2} + \\| v \\| ^ {2} + 2 \\mathrm{Re} (\\langle u | v \\rangle) \\\\[0.4em]\n>  &\\leq \\| u \\| ^ {2} + \\| v \\| ^ {2} + 2 | \\langle u | v \\rangle | \\\\[0.4em]\n>  &\\leq \\| u \\| ^ {2} + \\| v \\| ^ {2} + 2 \\| u \\| \\| v \\| \\quad \\text { by   Eq.   (5.13) } \\\\[0.4em]\n>  &= (\\| u \\| + \\| v \\|) ^ {2}.\n> \\end{aligned}\n> $$\n>\n> 对<a href=\"#equation-5-14\" class=\"cross-reference\" id=\"xref-02-complex-inner-product-spaces-8\" data-reference=\"equation-5-14\">式 (5.14)</a> 的三角不等式取平方根即得。\n",
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