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        "quote": "\n\n> [!theorem] 定理（Groenewold–van Hove）\n> 不存在映射 $f\\mapsto O_f$，将 $\\mathbf R^2$ 上的多项式映到作用在 $L^2(\\mathbf R)$ 上的自伴算符，并满足\n>\n> $$\n> O_{\\{f,g\\}}=-\\frac{i}{\\hbar}[O_f,O_g]\n> $$\n>\n> 以及\n>\n> $$\n> O_p=P,\\quad O_q=Q\n> $$\n>\n> 对于 $\\mathbf R^2$ 上函数所成的任意李子代数，只要次数不超过二的多项式所成子代数是其真子代数，以上条件就不可能同时成立。\n\n> [!proof]- 证明\n> 详细证明见[8]的[第 5.4 节](../chapter-05/04-lie-algebra-representations)、[26]的[第 4.4 节](../chapter-04/04-inner-products)或[37]的[第 16 章](../chapter-16/index#section-16)。概要而言，证明先表明，三次多项式的泊松括号会产生更高次多项式；而且，对于次数三及以上的多项式，不存在次数有统一上界的有限维子代数。定理假设迫使三次项采用某些特定的算符排序；随后利用同一个四次多项式可写成两个不同泊松括号的事实，在四次项中导出矛盾：\n>\n> $$\n> q^2p^2=\\frac13\\{q^2p,p^2q\\}=\\frac19\\{q^3,p^3\\}\n> $$\n",
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        "quote": "\n\n> [!theorem] Theorem (Groenewold-van Hove)\n> There is no map $f\\mapsto O_f$ from polynomials on $\\mathbf R^2$ to self-adjoint operators on $L^2(\\mathbf R)$ satisfying\n>\n> $$\n> O_{\\{f,g\\}}=-\\frac{i}{\\hbar}[O_f,O_g]\n> $$\n>\n> and\n>\n> $$\n> O_p=P,\\quad O_q=Q\n> $$\n>\n> for any Lie subalgebra of functions on $\\mathbf R^2$ in which the subalgebra of polynomials of degree at most two is a proper subalgebra.\n\n> [!proof]- Proof\n> For a detailed proof, see [section 5.4](../chapter-05/04-lie-algebra-representations) of [8], [section 4.4](../chapter-04/04-inner-products) of [26], or [chapter 16](../chapter-16/index#section-16) of [37]. In outline, the proof begins by showing that Poisson brackets of degree-three polynomials produce higher-degree polynomials; moreover, for degree three and above there are no finite-dimensional subalgebras consisting of polynomials of bounded degree. The theorem’s assumptions force certain specific operator-ordering choices in degree three. These yield a contradiction in degree four, because the same degree-four polynomial has two different expressions as a Poisson bracket:\n>\n> $$\n> q^2p^2=\\frac13\\{q^2p,p^2q\\}=\\frac19\\{q^3,p^3\\}\n> $$\n",
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