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        "quote": "> [!example] <a class=\"object-permalink\" href=\"#example-13-9\">例 13.9</a> \n>\n> $\\alpha$是测度空间$X$上的平方可积函数构成的希尔伯特空间$L^2(X)$上的有界可测函数，<u id=\"concept-13-multiplication-operator\" class=\"concept-term\" data-concept-identity=\"urn:uuid:d9cfc0e8-4d07-4144-9b86-a6fa7b076397\" data-concept-route=\"/concept-identities#concept-d9cfc0e8-4d07-4144-9b86-a6fa7b076397\">乘法算符(multiplication operator)</u>$A_\\alpha:L^2(X)\\rightarrow L^2(X)$，定义成$A_\\alpha (f)=\\alpha f$是一个有界线性算符，因为$\\alpha f$对于每个$f\\in L^2(X)$，而且是平方可积的因为\n>\n> $$\n> |\\alpha f|^{2} \\leq M^{2}|f|^{2} \\quad \\text { 其中 } \\quad M=\\sup _{x \\in X}|\\alpha(x)| .\n> $$\n>\n> 乘法算符在$L^2(X)$空间上是良定义的，因为$f$和$f'$几乎处处相等，$f\\sim f'$于是$\\alpha f\\sim \\alpha f'$，于是我们用$A_\\alpha f$来代替$A_\\alpha [f]$并无歧义，线性性显然，而有界性源于\n>\n> $$\n> \\left\\|A_{\\alpha} f\\right\\|^{2}=\\int_{X}|\\alpha f|^{2} \\mathrm{~d} \\mu \\leq M^{2} \\int_{X}|f|^{2} \\mathrm{~d} \\mu=M^{2}\\|f\\|^{2}\n> $$",
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        "quote": "> [!example] <a class=\"object-permalink\" href=\"#example-13-9\">Example 13.9</a> \n>\n> Let $\\alpha$ be any bounded measurable function on the Hilbert space $L ^ { 2 } ( X )$ of square integrable functions on a measure space $X$. The <u class=\"concept-term\" data-concept-identity=\"urn:uuid:d9cfc0e8-4d07-4144-9b86-a6fa7b076397\" data-concept-route=\"/concept-identities#concept-d9cfc0e8-4d07-4144-9b86-a6fa7b076397\" id=\"first-bf78e829304ec69ff626-en\">multiplication operator</u> $A_{\\alpha}:L^2(X)\\to L^2(X)$ defined by $A _ { \\alpha } ( f ) = \\alpha f$ is a bounded linear operator, for $\\alpha f$ is measurable for every $f \\in L ^ { 2 } ( X )$ , and it is square integrable since\n>\n> $$\n> | \\alpha f | ^ {2} \\leq M ^ {2} | f | ^ {2} \\quad \\text { where } \\quad M = \\sup _ {x \\in X} | \\alpha (x) |.\n> $$\n>\n> The multiplication operator is well-defined on $L ^ { 2 } ( X )$ , for if $f$ and $f ^ { \\prime }$ are equal almost everywhere, $f \\sim f ^ { \\prime }$ , then $\\alpha f \\sim \\alpha f^{\\prime}$ ; thus there is no ambiguity in writing $A _ { \\alpha } f$ for $A _ { \\alpha } [ f ]$ Linearity is trivial, while boundedness follows from\n>\n> $$\n> \\| A _ {\\alpha} f \\| ^ {2} = \\int_ {X} | \\alpha f | ^ {2} \\mathrm{d} \\mu \\leq M ^ {2} \\int_ {X} | f | ^ {2} \\mathrm{d} \\mu = M ^ {2} \\| f \\| ^ {2}.\n> $$",
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