8.6 Harmonic forms and -cohomology groups
The th -cohomology group is defined by
An element is an equivalence class of -closed forms of bidegree which differ from by a -exact form,
Clearly is a complex vector space. Similarly to the de Rham cohomology groups, the -cohomology groups of are trivial, that is, all the closed -forms are exact. The -cohomology groups measure the topological non-triviality of a complex manifold .
8.6.1 The adjoint operators and
Let be a Hermitian manifold with . Define the inner product between by
where is the Hodge defined by
where is computed according to (7.173) extended to . [Remark: * maps an -form to an -form since it acts on a basis of , up to an irrelevant factor, as
Note that the above -symbols are the only non-vanishing components in a Hermitian manifold. Now it follows that
We define the adjoint operators and of and by
The operators and change the bidegrees as and . Clearly . Noting that a complex manifold is even dimensional as a differentiable manifold, we have (see (7.184a))
Proof
Let and . If we note that and hence , we find that
where use has been made of the facts , and (7.176a). If (8.109) is integrated over a compact complex manifold with no boundary, we have
The second term is
We finally find , namely . The other formula .
As a corollary of proposition 8.3, we have
8.6.2 Laplacians and the Hodge theorem
Besides the usual Laplacian , we define other Laplacians and on a Hermitian manifold,
An -form which satisfies ( ) is said to be -harmonic ( -harmonic). If ( ), satisfies ( ).
We have the complex version of the Hodge decomposition. Let be the set of -harmonic -forms,
Theorem 8.8 · Hodge's theorem
has a unique orthogonal decomposition:
namely an -form is uniquely expressed as
where , and .
The proof is found in lecture 22, Schwartz (1986), for example. If is -closed, we have . Then implies . Thus, any closed -form is written as , . This shows that . Note also that since for . Moreover, since is orthogonal to . Then it follows that . If denotes the projection operator to a harmonic -form, has a unique harmonic representative .
8.6.3 Laplacians on a Kähler manifold
In a general Hermitian manifold, there exist no particular relationships among the Laplacians , and . However, if is a Kähler manifold, they are essentially the same. [Note that the Levi-Civita connection is compatible with the Hermitian connection in a Kähler manifold.]
Let be a Kähler manifold. Then
The proof requires some technicalities and we simply refer to Schwartz (1986) and Goldberg (1962). This theorem puts constraints on the cohomology groups of a Kähler manifold . A form which satisfies also satisfies . Let be a holomorphic -form; . Since contains no in its expansion, we have , hence . According to theorem 8.9, we then have , that is any holomorphic form is automatically harmonic with respect to the Kähler metric. Conversely implies , hence every harmonic form of bidegree is holomorphic.
8.6.4 The Hodge numbers of Kähler manifolds
The complex dimension of is called the Hodge number . The cohomology groups of a complex manifold are summarized by the Hodge
diamond,
These Hodge numbers are far from independent as we shall see later.
Let be a Kähler manifold with . Then the Hodge numbers satisfy
(a) (8.116)
(b) (8.117)
Proof
(a) If is harmonic, it satisfies . Then the -form is also harmonic, since (note that ). Thus, for any harmonic form of bidegree , there exists a harmonic form of bidegree and vice versa. Thus, it follows that . (b) Let and . Then is a volume element and it can be shown (Schwartz 1986) that defines a non-singular map , hence the duality between and . This shows that is isomorphic to as a vector space and it follows that hence .
Accordingly, the Hodge diamond of a Kähler manifold is symmetric about the vertical and horizontal lines. These symmetries reduce the number of independent Hodge numbers to if is even and if is odd.
In a general Hermitian manifold, there are no direct relations between the Betti numbers and the Hodge numbers. If is a Kähler manifold, however, theorem 8.11 establishes close relationships between them.
Let be a Kähler manifold with and . Then the Betti numbers ( ) satisfy the following conditions;
(a) (8.118)
(b) is even (8.119)
(c) (8.120)
Proof
(a) is a complex vector space spanned by -harmonic -forms, . Note also that, is a real vector space spanned by -harmonic -forms, . Then the complexification of is . Since is Kähler, any form which satisfies also satisfies and vice versa. Since
we find that
Noting that , we obtain .
(b) From (a) and (8.116), it follows that
Thus, must be even.
(c) The crucial observation is that the Kähler form is a closed real two-form, , and the real -form
is also closed, . We show that is not exact. Suppose for some . Then . It follows from Stokes’ theorem that
Since the LHS is the volume of , this is in contradiction. Thus, there is at least one non-trivial element of and we have proved that .
If a Kähler manifold is Ricci flat, there exists an extra relationship among the Hodge numbers, which further reduces the independent Hodge numbers, see Horowitz (1986) and Candelas (1988).
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