29.1 Non-degenerate bilinear forms
Concept links · terms present in this machine draft; source roles are unverified: vector space · complex inner product · orthogonal group · complexification
In the case of , the dual phase space, the Poisson bracket determines an antisymmetric bilinear form on , which, for a basis and two vectors
is given explicitly by
Matrices such that
make up the group and preserve Ω, satisfying
This choice of Ω is much less arbitrary than it looks. One can show that given any non-degenerate antisymmetric bilinear form on a basis can be found with respect to which it will be the Ω given here (for a proof, see [8]). This is also true if one complexifies , using the same formula for Ω, which is now a bilinear form on . In the real case the group that preserves Ω is called , in the complex case
To get a fermionic analog of this, all one needs to do is replace “nondegenerate antisymmetric bilinear form with “non-degenerate symmetric bilinear form . Such a symmetric bilinear form is actually something much more familiar from geometry than the antisymmetric case analog: it is just a notion of inner product. Two things are diferent in the symmetric case:
• The underlying vector space does not have to be even dimensional, one can take for any including n odd. To get a detailed analog of the bosonic case though, we will need to consider the even case
• For a given dimension , there is not just one possible choice of up to change of basis, but one possible choice for each pair of non-negative integers , such that . Given , any choice of can be put
in the form
For a proof by Gram-Schmidt orthogonalization, see [8].
We can thus extend our definition of the orthogonal group as the group of transformations g preserving an inner product
to the case arbitrary by:
Definition (Orthogonal group $O ( r , s , { \bf R } )
)O ( r , s , \mathbf { R } )r + sr + sg$ that satisfy
is the subgroup of matrices of determinant +1.
If one complexifies, taking components of vectors to be in , using the same formula for , one can change basis by multiplying the s basis elements by a factor of and in this new basis all basis vectors satisfy One thus sees that on , as in the symplectic case, up to change of basis there is only one non-degenerate symmetric bilinear form. The group preserving this is called . Note that on is not the Hermitian inner product (which is antilinear on the first variable), and it is not positive definite.
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原书 PDF · 印刷页 318、319、320、321、322、323、324、325
来源版本:2025-10-20
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